Using map data to predict the progeny of the cross a+b+/ab with ab/ab

Let f =the expected frequency of cross overs

Description genotype P f=.1 N=1000

Parental type one

a+ b+ (1-f)/2 .45 450
Parental type two a b (1-f)/2 .45 450

Recombinant

a+ b f/2 .05 50
Recombinant a b+ f/2 .05 50

Example: If genes a and b are twenty map units apart (ie. f= .2) what is the expected progeny from a cross between an organism that is heterozygous for a and b is test crossed to an organism that is ab/ab. Assume that one parent was a+ b/a+ b. What is the probability that the double recessive will be found in the progeny?

Description genotype P f=.2 N=1000

Parental type one

a+ b (1-f)/2 .40 400
Parental type two a b+ (1-f)/2 .40 400

Recombinant

a b f/2 .10 100
Recombinant a+ b+ f/2 .10 100

The answer is P = 0.10

How does this problem change for three linked loci?


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This web site is provided for instruction in Botany and Zoology 342

by Kenneth G. Wilson,
Professor of Botany
Miami University
wilsonkg@muohio.edu